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3.0 g of H(2) reacts with 29.0 g of O(2)...

3.0 g of `H_(2)` reacts with 29.0 g of `O_(2)` to yield `H_(2)O`.
Calculate the amount of one of the reactants which remains unreacted.

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To solve the problem of how much of one of the reactants remains unreacted when 3.0 g of \( H_2 \) reacts with 29.0 g of \( O_2 \) to yield water, we will follow these steps: ### Step 1: Write the balanced chemical equation The balanced chemical equation for the reaction between hydrogen and oxygen to form water is: \[ 2H_2 + O_2 \rightarrow 2H_2O \] ...
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