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{:(,"List-I",,"List-II"),("(P)","12 g of...

`{:(,"List-I",,"List-II"),("(P)","12 g of carbon",(1),"Atomic mass unit"),("(Q)","28 g of nitrogen",(2),"Gram atom"),("(R)","22400 cc",(3),"Gram molar volume"),("(S)",1.67xx10^(-24)g,(4),"Gram molecule"):}`

A

P-2, Q-4, R-3, S-1

B

P-1, Q-4, R-3, S-2

C

P-3, Q-2, R-1, S-4

D

P-4, Q-1, R-2, S-3

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to match the items in List-I with the corresponding items in List-II based on their definitions or properties. ### Step-by-Step Solution: 1. **Identify the first item in List-I: 12 g of carbon (P)** - The mass of 12 g of carbon corresponds to 1 mole of carbon atoms. - 1 mole of any substance contains Avogadro's number of particles (6.022 x 10²³). - This matches with the definition of a "Gram atom," which is the mass of 1 mole of an element in grams. - **Match:** (P) 12 g of carbon → (2) Gram atom 2. **Identify the second item in List-I: 28 g of nitrogen (Q)** - The mass of 28 g of nitrogen corresponds to 1 mole of nitrogen atoms (N₂), as the atomic mass of nitrogen is approximately 14 g/mol. - Therefore, 28 g represents 1 mole of nitrogen molecules. - This corresponds to the definition of a "Gram molecule," which is the mass of 1 mole of a molecular substance in grams. - **Match:** (Q) 28 g of nitrogen → (4) Gram molecule 3. **Identify the third item in List-I: 22400 cc (R)** - 22400 cc (or cm³) is the volume occupied by 1 mole of any gas at standard temperature and pressure (STP). - This is known as the "Gram molar volume." - **Match:** (R) 22400 cc → (3) Gram molar volume 4. **Identify the fourth item in List-I: 1.67 x 10^(-24) g (S)** - This value represents the mass of a single atom of carbon, which is expressed in atomic mass units (amu). - The atomic mass unit is defined as one twelfth of the mass of a carbon-12 atom. - **Match:** (S) 1.67 x 10^(-24) g → (1) Atomic mass unit ### Final Matches: - (P) 12 g of carbon → (2) Gram atom - (Q) 28 g of nitrogen → (4) Gram molecule - (R) 22400 cc → (3) Gram molar volume - (S) 1.67 x 10^(-24) g → (1) Atomic mass unit
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{:(" List-I"," List-II"),((P) "Four carbon atoms" ,(1) "Prop"),( (Q) "Three carbon atoms", (2) "Pent"),( (R ) "Five carbon atoms", (3) "But"),( (S) "Six carbon atoms", (4) "Hex"):}

{:(,"Column-I",,"Column-II"),("(A)","Atomic mass in grams","(p)","Mole"),("(B)","Gram molar mass","(q)","Gram atom"),("(C)","Avogadro's No.","(r)",6.022xx10^(23)),("(D)","22.4 L of any gas at N.T.P.","(s)","Molecular mass in grams"):}

{:(,"Column I",,"Column II"),("(A)","1 Hectogram","p)",10^(-6)" gram"),("(B)","1 Decagram","q)",10^(2)" gram"),("(C)","1 milli gram","r)","10 gram"),("(D)","1 micro gram","s)",10^(-3)" gram"):}

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State the following : (i) atomic mass (ii) gram atomic mass (iii) gram molar volume.

Here each question contains statements given in two columns which have to be matched. Statements in Column I are labelled as A,B,C and D. Whereas statements in column II are labelled as p,q,r and s. The answers to these questions have to be appropriately bublled as illustrated in the following example. If the correct matches are A-p, A-s, B-q, B-r, C-p, C-q and D-p, then the correctly bubbled 4xx4 matrix should look like the following. {:(,"Column I",,"Column II"),((A),"Atomic mass in grams ",p,"Mole"),((B),"Grams molar mass",q,"Grams atoms"),((C),"Avogadro's number",r,"Molecular mass in grams"),((D),"22.4 litres of any gas at NTP ",s,6.022xx10^(23)):}