`{:(,"List-I",,"List-II"),("(P)","Molarity",(1),W(g)//GEM),("(Q)","Normality",(2),n//W(kg)),("(R)","Molality",(3),n_(A)//(n_(A)+n_(B))),("(S)","Mole fraction",(4),W(g)//GMM):}`

Options

A. P-4, Q-1, R-3, S-2
B. P-4, Q-1, R-2, S-3
C. P-1, Q-3, R-4, S-2
D. P-2, Q-4, R-3, S-1

Answer

To solve the question of matching the concentration terms from List-I with their corresponding formulas from List-II, we will analyze each term step by step.

### Step 1: Identify the concentration term for (P) Molarity
- **Definition**: Molarity (M) is defined as the number of moles of solute per liter of solution.
- **Formula**: M = n/V, where n is the number of moles and V is the volume in liters.
- To express moles in terms of mass: n = W(g)/GMM (where W(g) is the mass of solute in grams and GMM is the gram molar mass).
- **Conclusion**: For (P) Molarity, the correct match is (4) W(g)//GMM.

### Step 2: Identify the concentration term for (Q) Normality
- **Definition**: Normality (N) is defined as the number of gram equivalents of solute per liter of solution.
- **Formula**: N = n_eq/V, where n_eq is the number of gram equivalents and V is the volume in liters.
- To express gram equivalents: n_eq = W(g)/GEM (where GEM is the gram equivalent mass).
- **Conclusion**: For (Q) Normality, the correct match is (1) W(g)//GEM.

### Step 3: Identify the concentration term for (R) Molality
- **Definition**: Molality (m) is defined as the number of moles of solute per kilogram of solvent.
- **Formula**: m = n/W(kg), where n is the number of moles and W(kg) is the mass of solvent in kilograms.
- **Conclusion**: For (R) Molality, the correct match is (2) n//W(kg).

### Step 4: Identify the concentration term for (S) Mole Fraction
- **Definition**: Mole fraction (χ) is defined as the ratio of the number of moles of a component to the total number of moles of all components in the mixture.
- **Formula**: χ_A = n_A/(n_A + n_B), where n_A is the number of moles of component A and n_B is the number of moles of component B.
- **Conclusion**: For (S) Mole Fraction, the correct match is (3) n_A//(n_A + n_B).

### Final Matches:
- (P) Molarity → (4) W(g)//GMM
- (Q) Normality → (1) W(g)//GEM
- (R) Molality → (2) n//W(kg)
- (S) Mole Fraction → (3) n_A//(n_A + n_B)

### Summary of Matches:
- (P) → (4)
- (Q) → (1)
- (R) → (2)
- (S) → (3)

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