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Calculate the kinetic energy of the ejec...

Calculate the kinetic energy of the ejected electron when ultra-violet radiation of frequency `1.6 xx 10^(15) s^(-1)` strikes the surface of potassium metal. Threshold frequency of potassium is `5 xx 10^(14) s^(-1) (h = 6.63 xx 10^(-34) Js)`.

Text Solution

Verified by Experts

Kinetic energy of the ejected electron is given by
K.E. `=hv-hv_(0)=h(v-v_(0))`
`v=1.6xx10^(15)" s"^(-1),v_(0)=5xx10^(14)" s"^(-1)`
`:.` K.E. `=(6.63xx10^(-34)" Js")xx(1.6xx10^(15)-5xx10^(14))s^(-1)`
`=(6.63xx10^(-34)" Js")xx(11xx10^(14)"s"^(-1))=7.29xx10^(-19)"J"`.
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