PASSAGE - I : The electron with the highest energy in an atom has the quantum numbers `n=4,l=1,m=0,s=1//2`
The orbital occupied by the electron by convention, is

Options

A. `4p_(x)`
B. `4p_(y)`
C. `4p_(z)`
D. any one of these.

Answer

To solve the problem, we need to identify the orbital occupied by the electron based on the given quantum numbers. The quantum numbers provided are:

- Principal quantum number (n) = 4
- Azimuthal quantum number (l) = 1
- Magnetic quantum number (m) = 0
- Spin quantum number (s) = 1/2

### Step-by-Step Solution:

1. **Identify the Principal Quantum Number (n)**:
- The principal quantum number (n) indicates the energy level of the electron. Here, n = 4 means the electron is in the fourth energy level.

2. **Identify the Azimuthal Quantum Number (l)**:
- The azimuthal quantum number (l) defines the shape of the orbital. For l = 1, the orbital type is a p orbital.

3. **Identify the Magnetic Quantum Number (m)**:
- The magnetic quantum number (m) specifies the orientation of the orbital. The possible values for m when l = 1 are -1, 0, and +1.
- Here, m = 0 indicates that the orbital is oriented along the z-axis.

4. **Determine the Orbital**:
- Since we have established that n = 4 and l = 1, we are dealing with a p orbital in the fourth energy level. The specific orientation given by m = 0 corresponds to the pz orbital.
- Therefore, the occupied orbital is 4pz.

### Final Answer:
The orbital occupied by the electron is **4pz**.