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One of the dimensions of the cuboid whos...

One of the dimensions of the cuboid whose volume is `16x^(2)-26x+10` is

A

`2`

B

`(8x-5)`

C

`(x-1)`

D

All of these

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The correct Answer is:
To find one of the dimensions of the cuboid whose volume is given by the polynomial \(16x^2 - 26x + 10\), we will factor the polynomial step by step. ### Step 1: Write down the volume expression The volume of the cuboid is given as: \[ V = 16x^2 - 26x + 10 \] ### Step 2: Factor out the common factor First, we can factor out the greatest common factor from the polynomial. Here, we can factor out \(2\): \[ V = 2(8x^2 - 13x + 5) \] ### Step 3: Factor the quadratic expression Next, we need to factor the quadratic expression \(8x^2 - 13x + 5\). We will look for two numbers that multiply to \(8 \times 5 = 40\) and add up to \(-13\). The numbers \(-8\) and \(-5\) satisfy this condition because: \[ -8 \times -5 = 40 \quad \text{and} \quad -8 + -5 = -13 \] ### Step 4: Rewrite the quadratic expression Now we can rewrite the quadratic expression: \[ 8x^2 - 8x - 5x + 5 \] ### Step 5: Group the terms Next, we will group the terms: \[ (8x^2 - 8x) + (-5x + 5) \] ### Step 6: Factor by grouping Now, we can factor out the common factors from each group: \[ 8x(x - 1) - 5(x - 1) \] ### Step 7: Factor out the common binomial Now we can factor out the common binomial \((x - 1)\): \[ (8x - 5)(x - 1) \] ### Step 8: Write the final factored form Now, substituting back into the volume expression, we have: \[ V = 2(8x - 5)(x - 1) \] ### Step 9: Identify the dimensions From the factored form, we can identify the dimensions of the cuboid: - One dimension is \(2\) - Another dimension is \(8x - 5\) - The third dimension is \(x - 1\) ### Conclusion Thus, one of the dimensions of the cuboid is: \[ \text{Dimension} = 2, \quad 8x - 5, \quad \text{or} \quad x - 1 \]
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x^(2)-10x+16

MTG IIT JEE FOUNDATION-POLYNOMIALS-EXERCISE (Multiple choice Question (Level-1))
  1. Factors of (a+b)^(3)-(a-b)^(3) are

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  2. The common quantity that must be added to each term of a^(2):b^(2) to ...

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  3. One of the dimensions of the cuboid whose volume is 16x^(2)-26x+10 is

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  4. find the value of x+y+z if x^(2)+y^(2)+z^(2)=18 and xy+yz+zx=9 .

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  5. Find the remainder when the polynomial f(x)=x^(3)-3x^(2)+4x+50 is div...

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  6. The value of a for which (x+a) is a factor of the polynomial x^(3)+ax^...

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  7. Factorisation of the polynomial sqrt(3)x^(2)+11x+6sqrt(3)

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  8. If x=-2 and x^(2)+y^(2)+2xy=0 , then find y .

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  9. If x+(1)/(x)=5 , then find the value of x^(2)+(1)/(x^(2)) .

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  10. Find the value of x^(3)-8y^(3)-36xy-216 , when x=2y+6 .

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  11. Simplify : (x^(3)-4-x+4x^(2))/(x^(2)+3x-4)

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  12. Which of the following is true if (x+1) and (x+2) are factors of p(x)=...

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  13. Factorise : 6x^(3)-5x^(2)-13x+12

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  14. If p(x)=x^(3)-3x^(2)-2x+4 , then find the value of [p(2)+p(-2)-p(0)] .

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  15. If p=2-a , then a^(3)+6ap+p^(3)-8 =

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  16. The polynomial p(x)=x^(4)-2x^(3)+3x^(2)-ax+3a when divided by (x+1) le...

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  17. The values of a and b so that the polynomial x^(3)-ax^(2)-13x+b has (x...

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  18. The product (a+b)(a-b)(a^2-a b+b^2)(a^2+a b+b^2) is equal to: a^6+b^6 ...

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  19. Posible factors of x^(4)+x^(3)-7x^(2)-x+6 are

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  20. If a+b+c=0 , then (a^2)/(b c)+(b^2)/(c a)+(c^2)/(a b)=\ 0 (b) 1 (...

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