In the given figure, PR `gt` PQ and PS bisects `angle` QPR. Prove that `angle PSR gt angle PSQ`.

In the given figure , AC gt AB and AD bisects angle BAC Prove that angle ADC gt ADB

In the given figure, PS = PR and /_TPS = /_QPR . Prove that PT = PQ .

In the given figure, PS=PR, angleTPS=angleQPR . Prove that PT=PQ .

In the given figure, PS is the median, bisecting angle P, then angleQPS is

In the given figure, AP_|_QR, PR gt PQ and PQ=PS . Show that ARgt AQ .

In the given figure, (QR)/(QS)= (QT)/(PR) and angle1 = angle2 then prove that trianglePQS ~ triangleTQR.

In figure, OP bisects angle BOC and OQ bisects angle AOC , then angle POQ is

In the figure,PR is the angle bisector of /_APQ. Prove that AB|_(|CD)

In the given figure, if PQ || RS, angle QPT=115^(@) and angle PTR=20^(@) , then angle SRT is

In Fig.6.15 angle PQR= angle PRQ, then prove that angle PQS= angle PRT.