Show that the diagonals of a parallelogram divide it into four triangles of equal area.

A diagonal of a parallelogram divides it into two triangles of equal area.

A diagonal of a parallelogram divides it into two congruent triangles.

A diagonal of a parallelogram divides it into two triangles of equal area. GIVEN : A parallelogram A B C D in which B D is one of the diagonals. TO PROVE : ar ( A B D)=a r( C D B)

Show that each diagonal of a parallelogram divide it into two congruent triangles. The following are the steps involved in showing the above result. Arrange them in sequential order. A) In triangleABC and triangleCDA , AB=DC and BC=AD (therefore opposite angles of parallelogram) AC=AC (common side). B) Let ABCD be a parallelogram. Join AC. C) By SSS congruence property, triangleABC ~=triangleCDA . D) Similarly, BD divides the triangle into two congruent triangles.

A diagonal of parallelogram divides it into two congruent triangles.

The diagonals of a parallelograms are equal .

Asserion (A) : The diagonals of a ||gm divide it into four triangle of equal area. Reason (R ) : A diagonal of a ||gm divides it into two triangle of equal area.

Show that a median of a triangle divides it into two triangles of equal areas.

Show that a median of a triangle divides it into two triangles of equal area.