Which of the following set of decimals are arranged in ascending order ?

Options

A. 2.910,2.019,2.109,2.119
B. 2.910,2.119,2.109,2.019
C. 2.019,2.109,2.119,2.910
D. 2.119,2.109,2.019,2.910

Answer

To determine which set of decimals is arranged in ascending order, we need to compare the given decimals step by step. Let's follow the steps to find the correct answer.

### Step-by-Step Solution:

1. **List the Given Decimals**:
Let's write down the decimals we need to compare. For this example, we will consider the set:
- 2.910
- 2.019
- 2.109
- 2.119

2. **Identify the Whole Number**:
All the decimals start with the whole number 2. Since they all have the same whole number, we will compare the decimal parts next.

3. **Compare the Tenths Place**:
Look at the tenths place (the first digit after the decimal point):
- 2.910 has a tenths place of 9
- 2.019 has a tenths place of 0
- 2.109 has a tenths place of 1
- 2.119 has a tenths place of 1

The smallest tenths place is 0 (from 2.019), followed by 1 (from 2.109 and 2.119), and then 9 (from 2.910).

4. **Compare the Hundredths Place**:
For the numbers with the same tenths place (2.109 and 2.119), we need to look at the hundredths place (the second digit after the decimal point):
- 2.109 has a hundredths place of 0
- 2.119 has a hundredths place of 1

Since 0 is less than 1, 2.109 is smaller than 2.119.

5. **Arrange in Ascending Order**:
Now we can arrange the decimals based on our comparisons:
- The smallest is 2.019
- Next is 2.109
- Then comes 2.119
- Finally, the largest is 2.910

Therefore, the ascending order of the decimals is:
- 2.019, 2.109, 2.119, 2.910

### Final Answer:
The set of decimals arranged in ascending order is:
- 2.019, 2.109, 2.119, 2.910

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