Home
Class 6
MATHS
Assertion : The sum of 27.8, 175.09 and ...

Assertion `:` The sum of 27.8, 175.09 and 685.7 is 888.59.
Reason `:` To subtract decimal numbers, we place them columnwise correctly in the place value table and subtract them in the same way as of whole numbers.

A

If both assertion and reason are true and reason is the correct explanation of assertion

B

If both assertion and reason are true but reason is not the correct explanation of assertion.

C

If assertion is true but reason is false.

D

If assertion is false but reason is true.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to verify the assertion that the sum of 27.8, 175.09, and 685.7 is 888.59. We will follow these steps: ### Step-by-Step Solution: 1. **Align the Numbers**: Write the numbers in a column, aligning them by the decimal point. This helps in adding them correctly. ``` 27.80 + 175.09 + 685.70 ``` 2. **Convert to Like Decimals**: Ensure all numbers have the same number of decimal places. Here, we can add zeros to make them all have two decimal places: - 27.8 becomes 27.80 - 175.09 remains 175.09 - 685.7 becomes 685.70 3. **Add the Numbers**: Start adding from the rightmost column (the hundredths place): - **Hundredths Place**: 0 + 9 + 0 = 9 - **Tenths Place**: 8 + 0 + 7 = 15 (write down 5 and carry over 1) - **Units Place**: 7 + 5 + 5 + 1 (carry) = 18 (write down 8 and carry over 1) - **Tens Place**: 2 + 7 + 8 + 1 (carry) = 18 (write down 8 and carry over 1) - **Hundreds Place**: 0 + 1 + 6 + 1 (carry) = 8 4. **Combine the Results**: Now, combine all the digits: ``` 888.59 ``` 5. **Conclusion**: The sum of 27.8, 175.09, and 685.7 is indeed 888.59, confirming the assertion. ### Final Answer: The assertion is true: The sum of 27.8, 175.09, and 685.7 is 888.59.
Promotional Banner

Topper's Solved these Questions

  • DECIMALS

    MTG IIT JEE FOUNDATION|Exercise EXERCISE( COMPREHENSION TYPE) (PASSAGE-I)|3 Videos

  • DECIMALS

    MTG IIT JEE FOUNDATION|Exercise EXERCISE( COMPREHENSION TYPE) (PASSAGE-II)|3 Videos

  • DECIMALS

    MTG IIT JEE FOUNDATION|Exercise EXERCISE( MATCH THE FOLLOWING ) ( LEVEL-2)|3 Videos

  • DATA HANDLING

    MTG IIT JEE FOUNDATION|Exercise Olympiad/HOTS Corner|10 Videos

  • FRACTIONS

    MTG IIT JEE FOUNDATION|Exercise OLYMPIAD /HOTS CORNER|20 Videos

Similar Questions

Explore conceptually related problems

A number when subtracted by 1/7 of itself gives the same value as the sum of all the angles of a triangle. What is the number ?

Assertion: The sum of 154.2 + 6.1 + 23 is 183 Reason: The result of addition is reported to the same number of decimal places as that of the term with least number of decimal places.

When 1/7 of a number is subtracted from the number itself, it gives the same value as the sum of all the angles of a triangle. What is the number?

Assertion : 1000 is the successor of 999. Reason : We get the successor of a whole number, if we subtract 1 from it.

The sum of the digits of a two-digit number is 9. If 27 is subtracted from the number, then the digits interchange their places. Find the number

Assertion : 2x + 3 = 8 = 2x + 3 - 3 = 8 - 3 implies 2x = 5 implies x = 5/2 Reason : If we add/ subtract a number to L.H.S. of an equation then, we should add/ subtract the same number to R.H.S. to balance an equation.

The sum of the digits of a two-digit number is 11. if 9 is subtracted from the number, then the digits interchagne their places. Find the number. The following steps are involved in solving the above problem. Arrange them in sequential order (A) Let the units digit be x. therefore , the tens digit is (11-x). therefore The number is 10(11-x)+x=110-9x . (B) Given that 110-9x-9=9x+11rArrx=5 . (C) Units digit is S and tens digit is 6 and the required number is 65. (D) The number formed by interchanging the digits is 10x+(11-x)=9x+11 .