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Compare and fill in the box with lt, gt...

Compare and fill in the box with `lt, gt` or =.
`18.8 + 3 ( 1)/( 5) + 7 ( 3)/( 5) square 16.2 + 4 ( 7 )/( 25) + 3 ( 1)/( 8)`

A

=

B

`gt`

C

`lt`

D

Can't be determined

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to compare the two expressions: **Expression 1:** \( 18.8 + 3 \frac{1}{5} + 7 \frac{3}{5} \) **Expression 2:** \( 16.2 + 4 \frac{7}{25} + 3 \frac{1}{8} \) ### Step 1: Convert mixed numbers to improper fractions 1. **For Expression 1:** - \( 3 \frac{1}{5} = 3 + \frac{1}{5} = \frac{15}{5} + \frac{1}{5} = \frac{16}{5} \) - \( 7 \frac{3}{5} = 7 + \frac{3}{5} = \frac{35}{5} + \frac{3}{5} = \frac{38}{5} \) So, Expression 1 becomes: \[ 18.8 + \frac{16}{5} + \frac{38}{5} \] 2. **For Expression 2:** - \( 4 \frac{7}{25} = 4 + \frac{7}{25} = \frac{100}{25} + \frac{7}{25} = \frac{107}{25} \) - \( 3 \frac{1}{8} = 3 + \frac{1}{8} = \frac{24}{8} + \frac{1}{8} = \frac{25}{8} \) So, Expression 2 becomes: \[ 16.2 + \frac{107}{25} + \frac{25}{8} \] ### Step 2: Convert decimals to fractions - \( 18.8 = \frac{188}{10} \) - \( 16.2 = \frac{162}{10} \) ### Step 3: Find a common denominator for the fractions - The least common multiple (LCM) of 5, 25, and 8 is 200. ### Step 4: Convert all fractions to have a common denominator 1. **For Expression 1:** - \( \frac{16}{5} = \frac{16 \times 40}{5 \times 40} = \frac{640}{200} \) - \( \frac{38}{5} = \frac{38 \times 40}{5 \times 40} = \frac{1520}{200} \) So, Expression 1 becomes: \[ \frac{1880}{200} + \frac{640}{200} + \frac{1520}{200} = \frac{1880 + 640 + 1520}{200} = \frac{4040}{200} \] 2. **For Expression 2:** - \( \frac{107}{25} = \frac{107 \times 8}{25 \times 8} = \frac{856}{200} \) - \( \frac{25}{8} = \frac{25 \times 25}{8 \times 25} = \frac{625}{200} \) So, Expression 2 becomes: \[ \frac{1620}{200} + \frac{856}{200} + \frac{625}{200} = \frac{1620 + 856 + 625}{200} = \frac{3101}{200} \] ### Step 5: Compare the two expressions Now we compare: \[ \frac{4040}{200} \quad \text{and} \quad \frac{3101}{200} \] Since \( 4040 > 3101 \), we can conclude: \[ 18.8 + 3 \frac{1}{5} + 7 \frac{3}{5} > 16.2 + 4 \frac{7}{25} + 3 \frac{1}{8} \] ### Final Answer Thus, we fill in the box with: \[ \text{gt} \] ---
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