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The diagonals of a parallelogram bisect each other.

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If A (1,-6) , B= (5,-2) and C = (12 , -9) are the three consecutive vertices of a parallelogram ,then the find fourth vertex . The following are the steps involved in solving the above problem . Arrange them in sequential order from beginning to end. (A) (5 +x)/(2) = (13)/(2) , (-2 +y)/(2) = (-15)/(2) implies x = 8 and y = -13 . Therefore , D = (8 , -13) . (B) therefore ((5 +x)/(2) , (-2+y)/(2)) = ((1+12)/(2) , (-6-9)/(2)) (C) Let the fourth vertex be D = (x , y) . (D) We know that diagonals of a parallelogram bisect each other.

The diagonals of parallelogram bisect each other ( True/ False)

if diagonals of a parallelogram bisect each other,prove that its a rhombus

The diagonals of the quadrilateral whose sides are 3x+2y+1=0,3x+2y+2=02x+3y+1=0 and 2x+3y+2 include an angle (pi)/(2) Diagonals of a parallelogram bisect each other

Assertion: Diagonals of a rhombus bisect each other. Reason: Even rhombus is a parallelogram and diagonals of parallelogram bisect each other.

Write the antecedent and the consequent part the following statement : The diagonals parallelogram bisect each other .

If A(-2, -1), B(a,0), C(4,b) and D(1,2) are the vertices of a parallelogram. Complete activity to find the values of a and b. Activity : A(-2,-1), B(a,0), C(4,0) and D(1,2) are the vertices of a parallelogram Diagonals of parallelogram bisect each other :. midpoint of diagonal AC = Midpoint of diagonal BD By midpoint formula, ((-2 + 4)/(2), (-1 + b)/(2)) = ((a + 1)/(2), (square)/(square)) :. (square, (-1 + b)/(2)) = ((a + 1)/(2), 1) {:( :. square = (a + 1)/(2)),("on simplifying, we get"),(a = square):}|:{:((-1 + b)/(2) = square),("on simplifying, we get"),(b = square):}

Diagonals of a parallelogram intersect each other at point Q. If AQ =5, BQ =12and AB =13, then show that ABCD is a rhombus.

Prove using vectors: The diagonals of a quadrilateral bisect each other iff it is a parallelogram.

If the diagonals of a quadrilateral bisect each other,then the quadrilateral is a parallelogram.

MTG IIT JEE FOUNDATION-CONGRUENCE OF TRIANGLES -Solved Examples
  1. In the given figure, we have PQ = SR and Pr = SQ. Prove that: ang...

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  2. In the given figure, we have C is the mid-point of AB and DA = DB. P...

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  3. The diagonals of a parallelogram bisect each other.

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  4. In the adjoining figure, DeltaABC is an isosceles triangle in which AB...

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  5. In the adjoining figure, DeltaABC is an isosceles triangle in which AB...

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  6. In the adjoining figure, DeltaABC is an isosceles triangle in which AB...

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  7. In the adjoining figure, DeltaABC is an isosceles triangle in which AB...

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  8. In the adjoining figure, DeltaABC is an isosceles triangle in which AB...

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  9. In the adjoining figure, DeltaABC is an isosceles triangle in which AB...

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  10. In the given figure, KK' and LL' are equal and perpendicular to AC. Sh...

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  11. In the figure, it is given that LM = NM, MLbotPQandMNbotPR. Prove that...

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  12. In the adjoining figure, DeltaABC is an isosceles triangle in which AB...

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  13. In the adjoining figure, DeltaABC is an isosceles triangle in which AB...

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  14. Show that the diagonals of a rhombus bisect each other at right ang...

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  15. If the opposite sides of a quadrilateral are equal, prove that the qua...

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  16. In both the given figures, AB = AC and DB = DC. Prove that angleABD=an...

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  17. In the given figure, triangles ABC and DCB are right angled at A and D...

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  18. In the given figure, AB = AC and AD = AE. Prove that: DeltaABD~=Delt...

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  19. In the given figure, AB = AC and AD = AE. Prove that: BD = CE

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  20. A B is a line segment. A X\ a n d\ B Y are two equal line segments ...

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