Home
Class 7
MATHS
In the given figure, angleBAC=angleCDBan...

In the given figure, `angleBAC=angleCDBandangleACB=angleDBC`. Prove that AC = DB.

Promotional Banner

Topper's Solved these Questions

  • CONGRUENCE OF TRIANGLES

    MTG IIT JEE FOUNDATION|Exercise Subjective Problems (Long Answer Type)|10 Videos
  • CONGRUENCE OF TRIANGLES

    MTG IIT JEE FOUNDATION|Exercise Olympiad/HOTS Corner|10 Videos
  • CONGRUENCE OF TRIANGLES

    MTG IIT JEE FOUNDATION|Exercise Subjective Problems (Very Short Answer Type)|10 Videos
  • COMPARING QUANTITIES

    MTG IIT JEE FOUNDATION|Exercise Olympaid/HOTS Corner|20 Videos
  • DATA HANDLING

    MTG IIT JEE FOUNDATION|Exercise Olympiad / Hots Corner |20 Videos

Similar Questions

Explore conceptually related problems

In the given figure, Ab = CD and angleABC=angleDCB=90^(@) . Prove that AC = DB.

AB = Dc and angleABC=angleDCB . Prove that: AC = DB

In the adjoining figure, angleBAC=angleBDC and angleABC=angleBCD . Prove that : (i) DeltaABC cong DeltaDCB (ii) DeltaABE cong DeltaDCF .

In the given figure , AB = CD , CE = BF and angle ACE = angle DBF . Prove that triangle ACE cong triangle DBF

In the given figure, (AD)/(DB)=(AE)/(EC) and angle ADE=angle ACB . Prove that Delta ABC is an isosceles triangle.

In the given figure, AB = AD and angleBAC=angleDAC . Then (i) Delta ____ ~=DeltaABC .

In the given figure, AB = AD and angleBAC=angleDAC . Then (ii) BC = ____.

In the given figure, AB = AD and angleBAC=angleDAC . Then (iii) angleBCA = ____.

In the given figure, prove that AC = BD .