AB = Dc and `angleABC=angleDCB`. Prove that:
DB = CA

AB = Dc and angleABC=angleDCB . Prove that: AC = DB

In the given figure, AB = AD and angle1=angle2 . Prove that : BC = DC

In the given figure, Ab = CD and angleABC=angleDCB=90^(@) . Prove that AC = DB.

In the given figure, AB"||"DC and angleD=angleC . Prove that : (i) AD = BC (ii) AC = BD

In the adjoining figure, AB=EF, BC=DE, angleABC=angleFED=90^(@) , prove that AD = CF .

In quadrilateral ABCD, AB=DC and AD=BC. Prove that the sides AB and DC are parallel to each other.

In both the given figures, AB = AC and DB = DC. Prove that angleABD=angleACD .

The incircle of an isosceles triangle ABC, in which AB = AC, touches the sides BC, CA and AB at D, E and F respectively . Prove that BD = DC.

Given AD=DC and DB biscets angleADC . (i) Prove that, DeltaADB cong DeltaCDB (ii) If angleABD=48^(@) , find angleCBD .