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Simplify : (root6(27)-sqrt(6(3)/4))^(2)...

Simplify : `(root6(27)-sqrt(6(3)/4))^(2)`

A

`3/4`

B

`sqrt3/2`

C

`root3(3)/4`

D

`3/2`

Text Solution

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The correct Answer is:
a
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MTG IIT JEE FOUNDATION-CUBES AND CUBE ROOTS-Olympiad/HOTS Corner
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  13. (root3(1.728)-root3(0.216))/(root3(2.197)-root3(0.343))=

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  17. root3(1.728)/root3(13.824)xxroot3(4.096)/root3(216)=

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  19. if x=root3 (13(103)/125), then the value of x is

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