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MTG IIT JEE FOUNDATION-CUBES AND CUBE ROOTS-Olympiad/HOTS Corner
- Simplify : (root6(27)-sqrt(6(3)/4))^(2)
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- By what least number 3600 must be multiplied to make it a perfect cube...
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- The value of sqrt(0.00001225/(0.00005329))-root3(sqrt0.000064) is
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- Evalution : root3(-0.000008/(-0.000216))
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- Evalution : root3(0.008)-root3(-512) +root3(2.197)
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- (3root3(13824))/(2root3(-15625))+(2root3(-13824))/root3(5832)=
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- Cube root of a number when divided by the smallest prime number gives ...
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- If a number has digit 2 at unit place, then its cube has digit at its...
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- Which of the following in incorrect?
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- root(3)(1- 127/343) के बराबर है?
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- If root3(x/729)+root3((8x)/729)+root3((27x)/5832)=1 , then find the va...
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- (root3(3)+root3(2))(root3(9)+root3(4)-root3(6))=
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- (root3(1.728)-root3(0.216))/(root3(2.197)-root3(0.343))=
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- If 3^(9)+3^(12)+3^(15)+3^(n) is a perfect cube, n in N,then the value ...
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- if x=root3(2(93)/125), then the value of x is
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- if sqrtroot3(x xx 0.000009)=0.3 ,then the value of sqrtx is
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- root3(1.728)/root3(13.824)xxroot3(4.096)/root3(216)=
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- If root3(x/729)+root3((27x)/3375)=1, then find the value of x.
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- if x=root3 (13(103)/125), then the value of x is
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- Evaluate : root3(4096/64)+3root3(3375/125)
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