Home
Class 10
MATHS
Find the H.C.F. and L.C.M. of 30, 72 and...

Find the H.C.F. and L.C.M. of 30, 72 and 432 using the prime factorisation method.

Text Solution

AI Generated Solution

The correct Answer is:
To find the H.C.F. (Highest Common Factor) and L.C.M. (Lowest Common Multiple) of the numbers 30, 72, and 432 using the prime factorization method, we will follow these steps: ### Step 1: Prime Factorization of Each Number **For 30:** - The prime factors of 30 can be found by dividing by the smallest prime numbers. - 30 = 2 × 15 - 15 = 3 × 5 - Therefore, the prime factorization of 30 is: \[ 30 = 2^1 \times 3^1 \times 5^1 \] **For 72:** - Similarly, we factor 72. - 72 = 2 × 36 - 36 = 2 × 18 - 18 = 2 × 9 - 9 = 3 × 3 - Therefore, the prime factorization of 72 is: \[ 72 = 2^3 \times 3^2 \] **For 432:** - Now, we factor 432. - 432 = 2 × 216 - 216 = 2 × 108 - 108 = 2 × 54 - 54 = 2 × 27 - 27 = 3 × 9 - 9 = 3 × 3 - Therefore, the prime factorization of 432 is: \[ 432 = 2^4 \times 3^3 \] ### Step 2: Finding the H.C.F. To find the H.C.F., we take the lowest power of each common prime factor from the factorizations. - For the prime factor 2: - The powers are \(2^1\) (from 30), \(2^3\) (from 72), and \(2^4\) (from 432). - The minimum power is \(2^1\). - For the prime factor 3: - The powers are \(3^1\) (from 30), \(3^2\) (from 72), and \(3^3\) (from 432). - The minimum power is \(3^1\). - For the prime factor 5: - The powers are \(5^1\) (from 30), \(5^0\) (from 72), and \(5^0\) (from 432). - The minimum power is \(5^0\) (which means it is not included). Thus, the H.C.F. is: \[ H.C.F. = 2^1 \times 3^1 = 2 \times 3 = 6 \] ### Step 3: Finding the L.C.M. To find the L.C.M., we take the highest power of each prime factor from the factorizations. - For the prime factor 2: - The powers are \(2^1\) (from 30), \(2^3\) (from 72), and \(2^4\) (from 432). - The maximum power is \(2^4\). - For the prime factor 3: - The powers are \(3^1\) (from 30), \(3^2\) (from 72), and \(3^3\) (from 432). - The maximum power is \(3^3\). - For the prime factor 5: - The powers are \(5^1\) (from 30), \(5^0\) (from 72), and \(5^0\) (from 432). - The maximum power is \(5^1\). Thus, the L.C.M. is: \[ L.C.M. = 2^4 \times 3^3 \times 5^1 \] Calculating this: - \(2^4 = 16\) - \(3^3 = 27\) - \(5^1 = 5\) Now, multiplying these together: \[ L.C.M. = 16 \times 27 \times 5 \] Calculating \(16 \times 27 = 432\) and then \(432 \times 5 = 2160\). ### Final Answer: - H.C.F. = 6 - L.C.M. = 2160
Promotional Banner

Topper's Solved these Questions

  • REAL NUMBERS

    MTG IIT JEE FOUNDATION|Exercise NCERT Section (Exercise 1.1)|7 Videos
  • REAL NUMBERS

    MTG IIT JEE FOUNDATION|Exercise NCERT Section (Exercise 1.2)|15 Videos
  • QUADRATIC EQUATIONS

    MTG IIT JEE FOUNDATION|Exercise OLYMPAID/HOTS CORNER|15 Videos
  • SOME APPLICATIONS OF TRIGONOMETRY

    MTG IIT JEE FOUNDATION|Exercise OLYMPIAD /HOTS CORNER |20 Videos

Similar Questions

Explore conceptually related problems

Find the H.C.F. and L.C.M. of 38 and 10

Find the HCF and LCM of 6,72 and 120, using the prime factorisation method.

Find the L.C.M. and H.C.F. of 9, 117 and 729 by the prime factorisation method.

Find the H.C.F.and L.C.M.of 1152 and 1664 .

Find the HCF and LCM of 108,120 and 252 using prime factorisation method.

Find the HCF and the LCM of 72 and 120, using prime factorisation method.

Find the HCF and LCM of 15 , 18 and 45 , by the prime factorisation method .

Find the HCF and LCM of 126 and 156 using prime factorisation method.