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A hammer of mass 500g, moving at 50m//s,...

A hammer of mass `500g`, moving at `50m//s`, strikes a nail. The nail stops the hammer in a very short time of `0.01 s`. What is the force of the nail on the hammer?

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Force= Rate of change of momentum
`=(mv-mu)/t`
Here `m=500g=0.5 kg ,v=0ms^-1`
`u=50 ms^-1,t=0.01s`
`implies F=(-0.5 times 50)/0.01=-2500N`
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MTG IIT JEE FOUNDATION-FORCE AND LAWS OF MOTION-OLYMPIAD /HOTS CORNER
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