How much momentum will a dumb-bell of mass `10kg` transfer to the floor if it falls a height of `80 cm`? Take its downward acceleration to be `10 m//s^(2)`.

Explanation

Here `m=10kg,s=80cm=0.8m,a=10 ms^-2 u=0, v=? P=?`
From `v^2-u^2=2as,v^2-0=2 times 10 0.8=16`
or `v=sqrt16=4ms^-1`
Momentum transferred, p=mv=`10 times 4`
`=40 kg ms^-1`