A mass of 100g strikes the wall with speed `5ms^-1` at an angle as shown in figure and it rebounds With the same speed . If the contact time is `2 times 10^-3` sec , what is the force applied by the wall?

Options

A. `250sqrt3` to right
B. 250N to right
C. `250 sqrt3N` to left
D. 250 N to left

Answer

C

Explanation

Impulse=force `times ` dt
i.e, `(d(mv))/(dt) times dt`= change of momentum takng place in a short time.
`-mv sin theta-(+mv sin theta)=-2mv sin theta`
i.e., `-2 times 0.100 times 5 sqrt3/2=-0.500 sqrt3`
The force applied= rate of change of momentum
`=-(0.500 times sqrt3)/((2 times 10^-3 s))=250 sqrt3 N` to the left