In a rocket, fuel bums at the rate of 1 kg/s. This fuel is ejected from the rocket with a velocity of 60 km/s. This exerts a force on the rocket equal to

Options

A. 6000N
B. 60000N
C. 60N
D. 600N

Answer

B

Explanation

Rate of burning of fuel `((dm)/(dt))=1kg//s` and velocity of ejected fuel (v)=`60 km//s`
Force= Rate of change of momentum
`=(dp)/(dt)= (d(mv))/(dt))= v (dm)/(dt)=(60 times 10^3) times 1=60000N`