A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. If a force P is applied at the free end of the rope, the force exerted by the rope on the block is

Options

A. `(Pm)/((M+m))`
B. `(Pm)/((M-m))`
C. P
D. `(PM)/((M+m))`

Answer

D

Explanation

If a is the acceleration produced in the system then `a=P/((M+m))`
the force exerted by the rope of the block is `F=Ma=(MP)/((M+m))`