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Figure shows a rod of length l= 1m and m...

Figure shows a rod of length l= 1m and mass m=8kg. It is hinged at the end P . At the end Q a block of mass M=50kg is suspended at the point R which is at a distance equal to 25cm from end Q, a string is connected whose other end is connected to the wall.

The tension in the string is

A

600N

B

80N

C

1200N

D

800N

Text Solution

Verified by Experts

The correct Answer is:
C

For equilibrium about `P: sum pi p=0`
`therefore [(500)(1)+80(0.5)-(T sin 37^@)(0.75)]=0`
Torque produced by `T cos 37^@ N_x and N_Y` about the point P is equal is zero
`500+40-T(3/5)(0.75)=0T=(540(5))/(3(0.75))=1200N`
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