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Figure shows a rod of length l= 1m and m...

Figure shows a rod of length l= 1m and mass m=8kg. It is hinged at the end P . At the end Q a block of mass M=50kg is suspended at the point R which is at a distance equal to 25cm from end Q, a string is connected whose other end is connected to the wall.

The horizontal component `N_2` and vertical component `N_y` of the reaction at the end P are given by

A

`N_x=1300N,N_y=960N`

B

`N_x=960N,N_y=140N`

C

`N_x=960N,N_y=960N`

D

`N_x=1300N, N_y=1300N`

Text Solution

Verified by Experts

The correct Answer is:
B
For equilibrium `sum F_x=0`
`therefore T cos 37^@-N_x=0`
or `N_x=4/5 T=4/5 (1200)=960 N`
For equilibrium `sum F_y=0`
`therefore N_y- T sin 37^@+500+80=0`
or `N_y=(1200)(3/5)-500-80=140N`
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