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Block B lying on a table weighs w. The c...

Block B lying on a table weighs w. The coefficient of static friction between the block and the table is mu. Assume that the cord between B and the knot is horizontal. The maximum weight of the block A for which the system will be stationary is

Text Solution

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Weight of block B=W

Weight of block `A=W.`
T=tension in the string
Normal on block `B,N=W`
Friction force on block B, `f=mu N= mu W`
System will be in equilibrium , if
`T cos theta =f mu =W`
`T sin theta= W.`
Divide eqn (ii) By eqn (i) we get
`(sin theta)/(cos theta)= (W.)/(mu W) therefore W.= mu W tan theta`
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