The velocity (u)-time (t) graph of an object moving along a straight line is as shown is Fig. 2 (b) . 30. Calculate the distance covered by object between ` (i) t =0 to t=5 s` (ii) ` t=0 to t=10 s`.
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Explanation

At t = 5 s, u = 20 m/s at t = 10 s, v = 0 m/s
so, form v = u + at
`0 + 20 + a xx 5 rArr a = - 4 m//s^(2)`
so, distance covered from t = 5 s to t = 10 s is
`v^(2) = u^(2) + 2 as`
`(0)^(2) = (20) ^(2) - 2 xx 4 xx s `
`s = (400)/( 8) = 50 m`
So, total distance covered between 0 to 10 s = 80 + 50 = 130 m