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(123)^2,(77)^2,(82)^2,(161)^2,(109)^2.Wh...

`(123)^2,(77)^2,(82)^2,(161)^2,(109)^2`.Which would end with digit 1 ?

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The correct Answer is:
`161^(2)` and `109^(2)` would end in 1.
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