Home
Class 9
MATHS
ABC and DBC are two isosceles trianges ...

ABC and DBC are two isosceles trianges on the same base BC Show that `angle ABD = angle ACD.`

Promotional Banner

Topper's Solved these Questions

  • TRIANGLES

    SWAN PUBLICATION|Exercise EXERCISE 7.3|10 Videos
  • TRIANGLES

    SWAN PUBLICATION|Exercise EXERCISE 7.4|6 Videos
  • TRIANGLES

    SWAN PUBLICATION|Exercise OBJECTIVE TYPE QUESTIONS |20 Videos
  • SURFACE AREAS AND VOLUMES

    SWAN PUBLICATION|Exercise Objective Type Questions (Fill in the Blanks ) |7 Videos

Similar Questions

Explore conceptually related problems

ABC and DBC are two isosceles triangles are same base BC. Show that angleABD=angleACD

ABC and DBC are two isosceles triangles on the same base BC (See Fig. ). Show that angleABD = angleACD .

ABC and DBC are two isosceles triangles on the same base BC (See Fig. ). Show that angleABD = angleACD .

ABC and DBC are two isosceles triangles on the common base BC. Then :

ABC and DBC are two isosceles triangles on the common base BC. Then :

DeltaABC and DeltaDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (See Fig. ).If AD is extended to intersect BC at P, show that AP bisects angleA as well as angleD .

DeltaABC and DeltaDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (See Fig. ).If AD is extended to intersect BC at P, show that AP bisects angleA as well as angleD .

DeltaABC and DeltaDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (See Fig. ).If AD is extended to intersect BC at P, show that AP is the perpendicular bisector of BC.

DeltaABC and DeltaDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (See Fig. ).If AD is extended to intersect BC at P, show that AP is the perpendicular bisector of BC.

DeltaABC and DeltaDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (See Fig. ).If AD is extended to intersect BC at P, show that DeltaABD ~= DeltaACD .