A piston filled with 0.04 mol of an ideal gas expands reversibly from 50.0 mL to 375 mL at a constant temperature of `37.0^(@)C.` As it does so, it absorbs 208 J of heat. The values of q and w for the process will be: (R=8.314 J/mol K) (In 7.5=2.01)

Options

A. `q =- 208 J , w =0 208 J`
B. `q =- 208 J, w = + 20 8 J`
C. ` q = + 208 J, w = + 20 8 J`
D. `q = + 208 J, w =- 208 J`

Explanation

Process is isothermal reversible expansion, hence `Delta U = 0` Therefore according to first law of themodynamics `q =- w As q = + 208 J,` hence `w =0 208 J.`