The densities of graphite and diamond at298K are 2.25gcm and 3.31 `gcm^(-3),`respectively. If the standard Gibbs energy difference `(Delta G^(@))` is equal to 1895 J.`mol^(-1),` the pressure at which graphite will be transformed into diamond at 298K is.

Options

A. `11. 1 xx 10 ^(8) Pa `
B. `11. 1 xx 10 ^(7) Pa `
C. `11. 1 xx 10 ^(6) Pa`
D. `11. 1 xx 10 ^(10) Pa`

Explanation

`Delta G = p Delta V `
`1895 = p {((12)/(225) - (12)/(3.31))xx 10 ^(-6) m ^(3) }implies P = (1895)/(1. 7 xx 10 ^(-6)) = 1.11 47 xx 10 ^(9) P a = 11. 1 xx 10 ^(8) Pa`