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For a spontaneous reaction, the DeltaG, ...

For a spontaneous reaction, the `DeltaG`, equilibrium constant `(K)` and `E_("cell") ^(@)` will be, respectively,

A

`-ve, gt 1, + ve`

B

`+ ve, gt 1 - ve`

C

`- ve, lt 1 , - ve`

D

`- ve, gt 1, - ve`

Text Solution

Verified by Experts

According to the relationship between `Delta G, K and E _(cell) ^(@).` For a spontanneous process `Delta G` has to negative always, so that `K gt 1` because `Delta G =- 2. 303 RT log K . E _(cell) ^(@)` hs to be positive because `Delta G =- n FE ^(@).`
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