The specific heats of `l_(2)` in vapour and solid states are 0.031 and 0.055 cal/g respectively. The heat of sublimation of iodine at 200°C is `6.096 kcal mol^(-1).` The heat of sublimation of iodine at `250^(@)C` will be:

Options

A. `3.8 kcal mol ^(-1)`
B. `4.8 kcal mol ^(-1)`
C. `2.28 kcal mol ^(-1)`
D. `5.8 kcal mol ^(-1)`

Explanation

`I _(2 (s)) hArr I _(2 (g)) " " Delta C _(p) = (0.031 - 0. 055) xx 10 ^(-3) 254," "(Delta H _(2) - Delta H _(1))/( T _(2) - T _(1)) = Delta C _(P)`
`( Delta H _(2) - 6. 096)/(50) = ( 0.031 -0.055) xx 10 ^(-3) xx 254 implies Delta H _(2) = 5. 79 ` kcal `mol ^(-1)`