On the basis of following thermochemical data :`[Delta _(f) G ^(@)H^(+) (aq) = 0]`
` H _(2) O_((l)) to H _((aq)) ^(+) + OH _((aq)) ^(-) , Delta H = 57.32 kJ, H _(2 (g)) + (1)/(2) O _(2 (g)) to H _(2) O _((l)) , H _(2(g) )+ (1)/(2) O _(2 (g)) to H _(20) O _((l)) , Delta H = -286.2kJ` The value of enthalpy of formation of OH-ion at` 25^(@)C `is:

Options

A. `-22.88 kJ`
B. `-228.88 kJ`
C. `+228.88 kJ`
D. `-343.52 k`

Explanation

The equation for the formation of `OH ^(-) (aq) is : H _(2) (g) + (1)/(2) O _(2) to H ^(+) (aq) + OH ^(-) (aq)`
It is obtained by adding the two given equations : `Delta H = 57.32 + ( - 286. 2) = - 228. 88 kJ`