Oxidizing power of chlorine in aqueous solution can be determined by the parameters indicated below:
`(1)/(2) Cl _(2) (g) overset((1)/(2) Delta _(diss) H ^(@)) to Cl (g) overset( Delta _(a ) H ^(@)) to Cl ^(-) (g) overset(Delta _(lm) H ^(@)) to Cl ^(-) (aq)`The energy involved in the conversion of `(1)/(2) Cl _(2) (g) ` to `Cl ^(-) (g) ` (using the data, ` Delta _(diss) H ^(@)) (Cl _(2)) = 2400 kJ mol ^(-1) Delta _(eg) H ^(@) (Cl) =- 349 kJ mol ^(-1), Delta _(iyd) H ^(@) (Cl) =- 381 kJ mol ^(-1))`

Options

A. `+ 152 kJ mol ^(-1)`
B. `-610 kJ mol ^(-1)`
C. `-850 kJ mol ^(-1)`
D. `+ 120 kJ mol ^(-1)`

Explanation

Given that : `(1)/(2) Cl _(2) (g) to Cl ^(-) (aq) , Delta H = ?, Cl _(2) to 2 Cl , Delta H _(1) = 240 kJ mol ^(-1)`
`Cl to Cl ^(-) , Delta H _(2) =- 349 kJ mol ^(-1) ,Cl ^(-) overset("Aqueous")underset("medium") to Cl ^(-) (aq) , Delta H _(1) =- 381kJ mol ^(-1)`
Therefore, `Delta H = ( Delta H _(1))/(2) + Delta H _(2) + Delta H _(3) = (240)/(2) - 349 - 381 =- 610 kJ mol ^(-1)`