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H (2 (g)) + (1)/(2) O (2) to H (2) O ((l...

`H _(2 (g)) + (1)/(2) O _(2) to H _(2) O _((l)) , Delta H _(298 K) = - 68.32 kcal.` Enthalpy of vapourization of water at 1 atm and `25^(@)C` is `10.52 kcal.` The standard enthalpy of formation (in kcal) of water vapour at `25^(@)C` is

A

`10.52`

B

`-78.84`

C

`+57.80`

D

`-57.80`

Text Solution

Verified by Experts

The required equation is ` H _(2 (g)) + (1)/(2) O _(2 (g)) to H _(2) O _((g))`
The equation can be obtained s `H_(2 (g)) + (1)/(2) O _(2 (g)) to H _(2) O _((l)), Delta H _( 298K) = - 68.32 `kcal (1)
`H_(2) O _((l)) to H _(2) O _((g)) , " " Delta H = 10 . 5 2 kcal " "(2)`
Adding Eqs. (1) and (2), `H _(2(g)) + (1)/(2) O _(2 (g)) to H _(2) O _((g)), Delta H =- 57. 80` kcal
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