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Given the following thermo chemical equa...

Given the following thermo chemical equations:
`2NO _((g)) + O _(2 (g)) to 2 NO _(2 (g)) , Delta H ^(@) =- 113.2 kJ mol ^(-1)`, `2 N _(2) O_(2(g)) + 3 O _(2 (g)) to 4 NO _(2 (g)) , Delta H ^(@) =28.0 kJ mol ^(-1)` calculate `Delta H ^(@)` for this reaction, ` N _(2 ) O _(2 (g)) to 2 NO _((g))`

A

`-99.2 kJ mol ^(-1)`

B

`+ 99.2 kJ mol ^(-1`

C

`+ 101 . 2 kJ mol ^(-1)`

D

`- 101. 2 kJ mol ^(-1)`

Text Solution

Verified by Experts

First , we divide the second reaction by 2 ,
`N _(2) O (g) + (3)/(2) O _(2 )(g) to 2 NO _(2) (g) Delta H =- 14. 0 kJ mol ^(-1)`
Now, reversing the first reaction, we get
`2NO _(2) (g) to 2 NO (g) + O _(2) (g) Delta H =113. 2 kJ mol ^(-1)`
Adding the above reactions, we get
`({:(N _(2) O (g) + (3)/(2) O _(2 ) (g) to 2 NO _(2) (g), Delta H ^(0) =- 14.0 kJ mol ^(-1)),(2 NO _(2) (g) to 2 NO (g) to 2 NO (g), Delta H ^(0) = 113. 2 kJ mol ^(-1)):})/({:(N _(2) O (g) + (1)/(2) O _(2) (g) to 2 NO (g), Delta H ^(@) = + 99. 2 kJ mol ^(-1)):}`
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