The net work done through a series of changes reported in figure for an ideal gas is:

Options

A. `-600 kJ`
B. `-700 kJ`
C. `-1200 kJ`
D. `+ 1200 kJ`

Explanation

Net work done = Area covered by PV curve
Area of trapezium `= ((a +b)/( 2 )) h =- (( 5m ^(3) + 2m ^(3))/(2)) xx 2 xx 10 ^(5) Pa =- 7 xx 10^(5) J =- 700 kJ`