A cylinder of gas is assumed to contain ...

A cylinder of gas is assumed to contain 11.2 kg ofbutane `(C_(4)H_(10))`. If a normal family needs 20000 kJ of energ per day, the cylinder will last in (Given that `DeltaH` for combustion of butane is –2658 kJ)

20 days

25 days

23 days

24 days

Text Solution

Verified by Experts

Cylinder contains `11. 2 kg ` or 1993. 10 mole butane `[because` Molecular mass of butane = 58]
`because ` Energy released by 1 mole of butane `=- 2658`
`therefore `Energy released by `193. 10` mole of butane `=0 2658xx 193 . 10 = 5. 13 xx 10 ^(5) kJ`
`therefore ` cylinder wil last in `( 5. 13 xx 10 ^(5))/( 20000) = 25. 66 ~~26` days

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