The specific heat of silver is 0.0565 cal/`g^(@)C.` Assuming no heat loss, the final temperature, when 100 g of Ag at `40.0^(@)C` is immersed in 60.0 g of water at `10.0^(@)C,`

Options

A. `10.15 `
B. `12.58`
C. `40.00`
D. `19.16`

Explanation

Suppose final temperaure is t an Q = `ms Delta t`
Heat lost by silver `= 100 xx 0. 0565 xx (40 - t ) ,` Heat gained by water `= 60 xx 1 xx (t - 10)`
Heat lost by silver = heat gained by water .
`5. 65 xx (40 - t) = 60 ( t -10) therefore t = 12. 58 ^(@) C`