4.48 Lofan ideal gas at S.T.P requires 12 calories to raise its temperature by `15^(@)C` at constant volume. The `C_(p)` of the gas is:

Explanation

NO. of moles is `4.48 L ` of ideal gas at `STP = ( 4.48)/(22.4) = 0. 2`
Thus, to raise the temperatuer os `0.2 `mol of the ideal gas through `15 ^(@)C,` heat absoorbed = 12 cal.
`therefore` To raise the temperature of 1 mol of the gas through `1 ^(@)C,` heat absorbed `= (12)/(15) xx (1)/(0.2) = 4 `cal
lie ., `C _(v) = 4 cal therefore C _(p ) = C _(v) + R = 4 + 2 cal = 6 cal.`