A heated iron block at `127^(@)C` loses 300 J. of heat to the surroundings which are at a temperature of `27^(@). `In this process the total change in entropy for system and surroundings is `(1)/(x) JK ^(-1).` Find the value of x.

Explanation

`Delta _( sys) S = ( q _(sys))/( T _(sys)) =- ( 300)/( 273 + 127) = ( - 300)/ ( 400) = (-3)/( 4) IK ^(-1) Delta _(sys) S = (- q _(sys))/(T _(surr))=- ( 300)/(273 + 27) = ( 300)/(300) = + 1 JK ^(-1)`
`Delta _(("total")) Sor Delta _("universe") S = Delta _( sys) S = Delta _( "surr") S = (-3)/(4) + 1 = (1)/(4) = 0. 25 JK ^(-1) , therefore (1)/(x) = 0. 25 implies x = (1)/(0. 25) = 4`