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The latent heat of vaporization of liqui...

The latent heat of vaporization of liquid at 500 K and 1 atmospheric pressure is 10.0 kcal/mol. What will be. the change in internal energy of 3 mole of the liquid at the same temperature and pressure?

A

`27.0 kcal`

B

`13.0 kcal`

C

`-27.0 kcal`

D

`-13.0 kcal`

Text Solution

Verified by Experts

`3 H _(2) O (1) t 3 H _(2) O (g) , Delta n _(g) = 3`
`Delta H = Delta U + Delta n _(g) RT therefore Delta U = Delta H - Delta n _(g) RT = 10 xx 2 - 3 xx 2 xx 10 ^(-3) xx 500 = 27` kcal
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