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For a given exothermic reaction, K(P ) a...

For a given exothermic reaction, `K_(P ) and K_(P)'` are the equilibrium constants at temperature `T_(1)` and higher temperature `T_(2)` respectively: Assuming that heat of reaction is constant in temperature range between `T_(1) and T_(2)` it is readily observed that:

A

`K_(P) gt K'_(P)`

B

`K_(P) lt K'_(P)`

C

`K_(P) = K'_(P)`

D

`K_(P) = (1)/(K'_(P))`

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(p) gt K._(p)` if `T_(2) gt T_(1)`.
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