The solubility of `Pb SO _(4)` at `25 ^(@)C` is `1.1 xx 10 ^(-4)` mol/L. Then its solubility product `(K_(sp))` is:

Options

A. `1.21 xx 10^(-8)`
B. `12.1 xx 10^(-6)`
C. `121 xx 10^(-11)`
D. `1.21 xx 10^(-10)`

Answer

A

Explanation

`PbSO_(4)` is a binary electrolyte, hence its `K_(sp)` can be calculate as : `K_(sp) = S^(2) = [1.1 xx 10^(-4)]^(2) = 1.21 xx 10^(-8)`