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Given: N (2) (g) + 3 H (2) (g) hArr 2 NH...

Given: `N _(2) (g) + 3 H _(2) (g) hArr 2 NH _3 (g) , K _(1)`
`N _(2) (g) + O _(2) (g) hArr 2 NO (g) , K _(2)` ,
`H _(2) (g) + (1)/(2) O _(2) hArr H _(2) O (g) , K _(3)`
The equilibrium constant for
`2 NH _(3) (g) + (5)/(2) O _(2) (g) hArr 2 NO (g) + 3 H _(2) O (g)` will be

A

`K_(1)K_(2)K_(3)`

B

`(K_(1)K_(2))/(K_(3))`

C

`(K_(1)K_(3)^(2))/(K_(2))`

D

`(K_(2)K_(3)^(3))/(K_(1))`

Text Solution

Verified by Experts

The correct Answer is:
D
`K_(1) = ([NH_(3)]^(2))/([N_(2)][H_(2)]^(3)), K_(2) = ([NO]^(2))/([N_(2)][O_(2)]), K_(3) = ([H_(2)O])/([H_(2)][O_(2)]^(1//2))`
The equilibrium constant for `2NH_(3)(g) + (5)/(2)O_(2)(g) hArr 2NO(g) + 3H_(2)O(g)`
will be : `K = ([NO]^(2)[H_(2)O]^(3))/([NH_(3)]^(2)[O_(2)]^(5//2)) = (K_(2) xx K_(3)^(3))/(K_(1))`
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