The equilibrium of formation of phosgene is represented as: `CO (g) + Cl _(2) (g) hArr COCl _(2) (g)`
The reaction is carried out in a 500 ml flask. At equilibrium, 0.3 mol of phosgene, 0.1 mol of CO, and 0.1 mol of Cl, are present. The equilibrium constant of the reaction is

Options

A. 30
B. 15
C. 5
D. 25

Answer

B

Explanation

For the reaction , `CO (g) + Cl_(2)(g) hArr COCl_(2)(g)`. The equilibrium constant, `K_(c) = ([COCl_(2)])/([CO][Cl_(2)]), [COCl_(2)], [CO]` and `[Cl_(2)]` are 0.6, 0.2 and 0.2 respectively. Then, `K_(c )= (0.6)/(0.2 xx 0.2) = 15`