For the reaction, `H _(2 (g) )+ CO _(2) (g) hArr CO (g) + H _(2) O (g),` if the initial concentration of `[H _(2) ] =[CO _(2)]` and x mol`L ^(-1) ` of `H,_(2)` is consumed at equilibrium, the correct expression of `K_(P)` is:

Options

A. `(x^(2))/((1-x)^(2))`
B. `((1+x)^(2))/((1-x)^(2))`
C. `(1+x^(2))/((2+x)^(2))`
D. `(x^(2))/(1+x^(2))`

Answer

A

Explanation

`{:(,H_(2)(g)+,CO_(2)(g),hArr,CO(g) +,H_(2)O(g)),(t = 0," "x," "x,," "0," "0),(t = t_(Eq),1-x,1-x,," "x," "x):}`
`therefore K = ([CO][H_(2)O])/([H_(2)][CO_(2)]) = (x^(2))/((1-x)^(2))`