When `NaNO_(3)` is heated in a closed vessel, oxygen is liberated and `NaNO_(2)` is left behind. At equilibrium:

Options

A. Addition of `NaNO_(2)` favours reverse reaction
B. Addition of `NaNO_(2` favours forward reaction
C. Increasing temperatrature favours forward reaction
D. Decreasing pressure favoures reverse reaction

Answer

C

Explanation

`NaNO_(3(a)) hArr NaNO_(2(s)) + (1)/(2)O_(2(g)), Delta H = + v e`
Also `K_(p) = (P_(O_(2)))^(1//2)` and thus addition of `NaNO_(3)` or `NaNO_(2)` has no effect.