The equilibrium constant for, `H _(2 (g)) + CO _(2 (g)) hArr H _(2) O _((g)) + CO _((g)) is 1.80 at 1000 ^(@)C.` If 1.0 mole of `H_(2) ` and 1.0 mole of `CO_(2)` are placed in one litre flask, the final equilibrium concentration of CO at `1000^(@)C` will be: `0.573 M`, `0.385 M`, `5.73 M`, `0.295M`

Options

A. 0.573 M
B. 0.385 M
C. 5.73 M
D. 0.295 M

Answer

A

Explanation

`{:(CO_(2)+,H_(2),hArr,H_(2)O+, CO),(1,1,,0,0),((1-x),(1-x),,x,x):}`
`therefore K_(o) = (x^(2))/((1-x)^(2))` or `(x)/(1-x) = sqrt(K_(c ) = sqrt(1.8)`,
`therefore (x)/(1-x) = 1.34 therefore x = 0.573`