In the equilibrium, `2SO _(2 (g)) + O _(2(g)) hArr 2 SO _(3 (g))` the partial pressure of `SO _(2), O _(2) and SO _(3)` are 0.662,0.101 and 0.331 atm respectively. What should be the partial pressure of oxygen so that the equilibrium concentration of `SO _(2) and SO _(3)` are equal: `0.404 atm`, `1.01 atm`, `0.808 atm`, `0.2475 atm`

Options

A. 0.404 atm
B. 1.01 atm
C. 0.808 atm
D. 0.2475 atm

Answer

A

Explanation

`K_(p) = ((P_(SO_(3))^(2)))/((P_SO_(2))^(2)(P_(O_(2)))) = ((0.331)^(2))/((0.662)^(2) xx 0.101) = 2.475`
If `P_(SO_(3)) = P_(SO_(2))` then , `P_(O_(2)) = (1)/(K_(P)) = (1)/(2.475) = 0.404` atm